JavaScript

leetcode : 234. Palindrome Linked List : memory usage beats 98.70 % of javascript submissions

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Another memory success for one of my leetcode solutions

When reading the variables sonic and tails, remember the game, Sonic is always faster than Tails, which is why hes one step ahead.

//isPalindrome      - base function 
//getLength         - helper function
//reverseFromMiddle - helper function

//get Length of Linked List
const getLength = head => {
    let counter = 0
    while(head){
        head = head.next
        counter++
    }
    return counter
}

const reverseFromMiddle = (head,middleIndex)=>{
    let middleHead=null
    for(i=1;i<=middleIndex;i++){ //1 because head is already the first node
        head = head.next
    }
    // console.log(`reverseFromMiddle head is ${head.val}`)
    let sonic = head.next
    let tails = head
    tails.next = null
    while(sonic){
        let temp =tails
        tails=sonic
        sonic=sonic.next
        tails.next =temp
    }
    // console.log(`sonic is ${sonic}`)
    // console.log("tails is", tails)
    return tails
}

var isPalindrome = function(head) {
    //if we get an empty node counts as valid palindrome
    if(!head){return true} 
    //get the length of the Linked List
    let length = getLength(head);
    //calculate 1/2 point of node
    let middleIndex = ~~(length/2)
    //from 1/2 point of Linked List 
    // start reversing into a reversed Link List
    let middleHead = reverseFromMiddle(head,middleIndex)
    //compare 2 havles
    while(head && middleHead){
        if(head.val != middleHead.val){return false}
        head = head.next
        middleHead=middleHead.next
    }
    return true
};

runtime beats 55.40 % of javascript submissions

leetcode : Longest Common Prefix : simple JavaScript solution

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This is not the fastest solution’s by far, but I think that it is one of the more simple ones to understand.

var longestCommonPrefix = function(strs) {
    if(!strs[0]){return ""} //empty array case
    let lcp = "" //base case 
    //lcp can never be greater then first string 
    //so we can use it as the max length of our loop
    for(i=0;i<strs[0].length;i++){   
        let c=strs
            .map(s=>s[i])  //get all the i'th index letters 
            //get all the unique letters gathered in map
            .reduce((arr,char)=> arr.includes(char) ? arr : [...arr,char], [])
         if(c.length === 1){lcp += c[0]} //if unique letters == 1, keep looping
        else{break} //else loop is over
    }
    return lcp
};

leetcode : 344. Reverse String : memory usage beats 99.55 % of javascript submissions

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Nice, another leetcode challenge where I beat most of the submissions in memory.

This is most likely because people did not pay attention to the spec which says: “Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.” I took that to mean as you can only have one extra variable so that’s what I used

var reverseString = function(s) {
    for(i=0;i<~~(s.length/2);i++){
        let temp = s[i]
        s[i]=s[s.length-1-i]
        s[s.length-1-i] = temp
    }
};

Runtime could have been better. My runtime beats 15.26 % of javascript submissions.

leetcode : 867. Transpose Matrix

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This one took a while to get. Originally I was trying to transpose in place, but you cannot guarantee the input is a square, so in place won’t work.Not sure if even in C you can transpose in place for a rectangular input. There maybe some memory tricks there, but they definitely are not available for JavaScript

Code is commented to guide

var transpose = function(A) {
    //this problem we actually cant transpose in place
    //since we cannot guarantee that the input is a square
    
    const result = []
    const rowsLength = A[0].length
    const columnsLength = A.length
    
    for(i=0;i<rowsLength;i++){
        let column = []
        for(j=0;j<columnsLength;j++){
            //here we get all elements in a column from input array A
            //and add it to new array named column
            column.push(A[j][i])
        }
        //we take the variable column we generated above
        //and turn it into a row for output Array result
        result.push(column)
    }
    return result
};

JavaScript – Division get whole numbers using bitwise operators

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When you divide 9/5 in JavaScript you get 1.8, which is a fractional number. What if we only wanted a remainder-less whole number quotient, C integer style?

printf("%i",7/5);  /* C prints 1 */

Most often, you will see people use Math.floor

console.log(Math.floor(7/5)) // prints 1

Another method you can use is to use the bitwise NOT operator ~ to do the same thing

console.log(~~(7/5)) //prints 1

leetcode: Plus One : JavaScript submission beats 99.90% in memory usage

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What the problem is asking for is to take the array and treat the whole thing as an integer. So [1,2,3] is the number 123, and if you add 1 that is 124. Then you would return [1,2,4].

You cannot just add 1 to the end, because for [5,6,9] you would need to return [5,7,0]. 569 + 1 = 570

Another thing to consider is that if the input is [9,9,9] then the returned array is larger having values [1,0,0,0]. 999 + 1 = 1000

The code I used is below. You can’t use the join, convert to number trick since some of the inputs are too large and then are rounded up loosing the trailing digits.

var plusOne = function(digits) {
    // return (parseInt(digits.join(""))+1).toString().split("")
    //the above looses precision when the number is too large
 
    for(let i=digits.length-1;i>=0; i--){
        if(digits[i]<9){digits[i]=digits[i]+1; return digits}
        digits[i]=0
    }
    //if we are here the first value in array was a 9
    digits.unshift(1)
    return digits
};

My runtime only beat 10.41% of the solutions. Great on memory, poor on performance.

Bitwise XOR / caret ^ operator in JavaScript

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There is a XOR operator in JavaScript! Its the carrot symbol, ^, which is the symbol above the number 6 on a US keyboard.

In JavaScript the XOR operator can be written as such

x ^= y 	//shorthand
x = x ^ y 

The bitwise XOR assignment operator uses the binary representation of both operands, does a bitwise XOR operation on them and assigns the result to the variable.

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Assignment_Operators#Bitwise_XOR_assignment

The chances are if you are doing this in JavaScript its for a coding excessive where among an array of integers, all are duplicates except one. Thanks to the power of bitwise operations you just XOR all the values until you are left with a remainder. The gist of it is that two like numbers cancel each other out. To understand “how” take a deep dive into binary, which I may add in a future article. But to just “do”, look at the following

//this is pseudo code 
[3,4,5,4,3] //array with a single unique value
let x=0 // we will use this to handle our values 
//loop over every element
x^=3 //3
x^=4 //7
x^=5 //2
x^=4 //6
x^=3 //3

x is 5

Looping through the array we found the single unique value. The above won’t make sense in base10, you have to do it in binary if you want to make sense of it. Otherwise that is how to do it.

leetcode: reverse integer: correct answer marked wrong

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I was doing leetcode’s reverse integer which as it’s name implies expects an integer to be reverse. example: 562 should be returned as 265.

The website marked my solution wrong even though my solution returned a revered number. The testcase 1534236469 had returned 9646324351 by my solution. Leetcode expected 0

Screenshot of my submission detail

The reason this is happening is because leetcode expects to only deal with a “32-bit signed integer”, and the output is larger than the maximum value of a 32-bit signed integer.

The largest a 32 bit signed integer can be is 2,147,483,647. A bit smaller than 9,646,324,351. I adjusted my solution and now received an acceptance.

var reverse = function(x) {
    let isNegative = x < 0 || false
    let rArray = x.toString().split("")
    console.log("rArray is",rArray)
    if(isNegative){ rArray.shift()}
    let rInt = parseInt(rArray.reverse().join(""))
    if (rInt > 2147483647) {return 0}
    return (isNegative ? rInt - 2 * rInt : rInt)
};
//pseudocode
    //convert to string //split into array
    // if  negative is true shift first char
    //reverse array // convert to string //convert to num
    //if negative true, subtract 2 * x

React inline styles – merge two style objects

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I had two style objects that I needed to merge for a component. One was the style objects that makes the component look good, the other was to set the display visible or not.

I could get around it by wrapping the component in another div that would get the display style, but here is how to minimize your divs

const style1 = {color: ‘blue’}
const style2 = {display: ‘none’} //used with state that toggles visibility

<div style={Object.assign(style2, style1)} > </div>

The reason the display style should be first is because the key pairs from the second object are copied to the first. so style2 would now be

{display: ‘none’, color: ‘blue’}

 

Node Error : Promise.all is not a function

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Are you getting the message?

Promise.all is not a function

At first I was thinking is my node version out of date?

But the answer is actually that your Promise.all function inst receiving an array.