leetcode 202. Happy Number memory usage better than 100% JavaScript

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What the problem is asking for is

  • look at each digit separately
  • square the digit
  • sum all the squares
  • if the sum of the squares will eventually equal 1, its a happy number

To solve this problem you have to know a mathematical trick, else the loop will go on forever. Once n < 10, if n is 1 or 7 the number will be happy. Any other number will cause an infinite loop.

var isHappy = function(n) {
        if(n===1 || n===7){return true}
        return false
    let sum = 0
        let value = n % 10
        sum += value**2
        n -= value
        n /= 10
    if(sum ===1){return true} //I could leave this out...
    return isHappy(sum)

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